((5/4x^-0.5)y^0.5)=((5x^0.5)y^-0.5)

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Solution for ((5/4x^-0.5)y^0.5)=((5x^0.5)y^-0.5) equation:


D( x )

x < 0

x = 0

x < 0

x = 0

x = 0

x in (0:+oo)

(5/4)*x^-0.5*y^0.5 = 5*x^0.5*y^-0.5 // - 5*x^0.5*y^-0.5

(5/4)*x^-0.5*y^0.5-(5*x^0.5*y^-0.5) = 0

(5/4)*x^-0.5*y^0.5-5*x^0.5*y^-0.5 = 0

5/4*x^-0.5*y^0.5-5*x^0.5*y^-0.5 = 0

5*x^0.5*y^-0.5*(1/4*x^-1*y-1) = 0

1/4*x^-1*y = 1 // : 1/4*y

x^-1 = 4*y^-1

-1 < 0

1/(x^1) = 4*y^-1 // * x^1

1 = 4*x^1*y^-1 // : 4*y^-1

1/(4*y^-1) = x^1

x = 1/(4*y^-1)

(5*x^0.5)/(y^0.5) = 0

5*x^0.5*y^-0.5 = 0 // : 5*y^-0.5

x^0.5 = 0

x = 0

x in { 0}

x = 1/(4*y^-1)

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